Rogers to Seymour: Road Trip Guide & Distance

485.2 miles 780.8 km · straight line
582.2 miles estimated 937 km · driving distance
11h 43min estimated drive time
$56 - $69 estimated fuel cost
~1h 29min flight time
66° ENE bearing direction

How far is Rogers from Seymour?

The distance from Rogers to Seymour is 485.2 miles (780.8 km) as the crow flies. Seymour is located ENE of Rogers. By car, the driving distance is approximately 582.2 miles, taking about 11h 43min. A direct flight would take roughly 1h 29min. Both are located in United States — Rogers in Arkansas and Seymour in Indiana.

This is a solid day of driving. Be sure to take breaks every 2-3 hours to avoid driver fatigue, and plan your meals ahead of time. Heading East means you'll be driving into the sunrise if you start early. Keep your windshield clean for the best visibility.

Coordinates come from public place data for Rogers and Seymour. The driving distance is estimated from straight-line distance with a road-factor model, so confirm the route in your navigation app. Fuel, flight, bus, and train values are planning estimates and can change by date, provider, road closures, and border rules.

How to Get from Rogers to Seymour

Method Time Est. Cost Best For
Drive 11h 43min $56 - $69 Flexible stops
Fly ~1h 29min $80–200* Speed
Bus ~14h 4min $47–$87* Budget
Train ~11h 8min $70–$204* Comfort

Suggested Stops Between Rogers & Seymour

Quick Facts

Rogers
36.33°N, 94.12°W
America/Chicago
417m elevation
Seymour
38.96°N, 85.89°W
America/Indiana/Indianapolis
184m elevation
Explore more routes from Seymour

Did You Know?

  • At walking speed (3 mph), it would take about 162 hours of non-stop walking
  • By bicycle at 12 mph, the journey would take roughly 40 hours
  • You could travel this distance about 51.3 times to circle the Earth's equator
Data Sources & Estimate Notes GeoNames · OpenStreetMap · Driving distance estimated using road factor coefficients