Rogers to San Angelo: Road Trip Guide & Distance

494.2 miles 795.3 km · straight line
593 miles estimated 954.4 km · driving distance
11h 56min estimated drive time
$57 - $70 estimated fuel cost
~1h 30min flight time
229° SW bearing direction

How far is Rogers from San Angelo?

The distance from Rogers to San Angelo is 494.2 miles (795.3 km) as the crow flies. San Angelo is located SW of Rogers. By car, the driving distance is approximately 593 miles, taking about 11h 56min. A direct flight would take roughly 1h 30min. Both are located in United States — Rogers in Arkansas and San Angelo in Texas.

This is a solid day of driving. Be sure to take breaks every 2-3 hours to avoid driver fatigue, and plan your meals ahead of time. Since you'll be heading mostly West, pack a good pair of sunglasses if you plan to drive during the late afternoon to avoid the harsh sun glare.

Coordinates come from public place data for Rogers and San Angelo. The driving distance is estimated from straight-line distance with a road-factor model, so confirm the route in your navigation app. Fuel, flight, bus, and train values are planning estimates and can change by date, provider, road closures, and border rules.

How to Get from Rogers to San Angelo

Method Time Est. Cost Best For
Drive 11h 56min $57 - $70 Flexible stops
Fly ~1h 30min $80–200* Speed
Bus ~14h 19min $47–$89* Budget
Train ~11h 20min $71–$208* Comfort

Suggested Stops Between Rogers & San Angelo

Quick Facts

Rogers
36.33°N, 94.12°W
America/Chicago
417m elevation
San Angelo
31.46°N, 100.44°W
America/Chicago
562m elevation
Explore more routes from San Angelo

Did You Know?

  • At walking speed (3 mph), it would take about 165 hours of non-stop walking
  • By bicycle at 12 mph, the journey would take roughly 41 hours
  • You could travel this distance about 50.4 times to circle the Earth's equator
Data Sources & Estimate Notes GeoNames · OpenStreetMap · Driving distance estimated using road factor coefficients