Oxford, Ohio to Shenandoah: Road Trip Guide & Distance

349.7 miles 562.8 km · straight line
419.7 miles estimated 675.4 km · driving distance
8h 27min estimated drive time
$40 - $50 estimated fuel cost
~1h 12min flight time
99° E bearing direction

How far is Oxford, Ohio from Shenandoah?

The distance from Oxford, Ohio to Shenandoah is 349.7 miles (562.8 km) as the crow flies. Shenandoah is located E of Oxford, Ohio. By car, the driving distance is approximately 419.7 miles, taking about 8h 27min. A direct flight would take roughly 1h 12min. Both are located in United States — Oxford, Ohio in Ohio and Shenandoah in Virginia.

This is a solid day of driving. Be sure to take breaks every 2-3 hours to avoid driver fatigue, and plan your meals ahead of time. Heading East means you'll be driving into the sunrise if you start early. Keep your windshield clean for the best visibility.

Coordinates come from public place data for Oxford, Ohio and Shenandoah. The driving distance is estimated from straight-line distance with a road-factor model, so confirm the route in your navigation app. Fuel, flight, bus, and train values are planning estimates and can change by date, provider, road closures, and border rules.

How to Get from Oxford, Ohio to Shenandoah

Method Time Est. Cost Best For
Drive 8h 27min $40 - $50 Flexible stops
Fly ~1h 12min $80–200* Speed
Bus ~10h 8min $34–$63* Budget
Train ~8h 2min $50–$147* Comfort

Suggested Stops Between Oxford, Ohio & Shenandoah

Quick Facts

Oxford, Ohio
39.51°N, 84.75°W
America/New_York
283m elevation
Shenandoah
38.53°N, 78.35°W
America/New_York
1234m elevation
Explore more routes from Shenandoah

Did You Know?

  • At walking speed (3 mph), it would take about 117 hours of non-stop walking
  • By bicycle at 12 mph, the journey would take roughly 29 hours
  • You could travel this distance about 71.2 times to circle the Earth's equator
Data Sources & Estimate Notes GeoNames · OpenStreetMap · Driving distance estimated using road factor coefficients