Lake Mary to Sanford, Florida: Road Trip Guide & Distance

4 miles 6.4 km · straight line
5.2 miles estimated 8.3 km · driving distance
6min estimated drive time
$0 - $1 estimated fuel cost
~30min flight time · usually no direct flights
43° NE bearing direction

How far is Lake Mary from Sanford, Florida?

The distance from Lake Mary to Sanford, Florida is 4 miles (6.4 km) as the crow flies. Sanford, Florida is located NE of Lake Mary. By car, the driving distance is approximately 5.2 miles, taking about 6min. A direct flight would take roughly 30min. Both are located in United States.

This is a very short trip, perfect for a quick morning drive or an easy commute. Heading East means you'll be driving into the sunrise if you start early. Keep your windshield clean for the best visibility. Given the short distance, driving or taking a train is often faster and more convenient than dealing with airport security and flight boarding times.

Coordinates come from public place data for Lake Mary and Sanford, Florida. The driving distance is estimated from straight-line distance with a road-factor model, so confirm the route in your navigation app. Fuel, flight, bus, and train values are planning estimates and can change by date, provider, road closures, and border rules.

How to Get from Lake Mary to Sanford, Florida

Method Time Est. Cost Best For
Drive 6min $0 - $1 Flexible stops

Quick Facts

Lake Mary
28.76°N, 81.32°W
America/New_York
19m elevation
Sanford, Florida
28.80°N, 81.27°W
America/New_York
9m elevation
Explore more routes from Sanford, Florida

Did You Know?

  • At walking speed (3 mph), it would take about 1 hours of non-stop walking
Data Sources & Estimate Notes GeoNames · OpenStreetMap · Driving distance estimated using road factor coefficients