Knoxville to Seymour: Road Trip Guide & Distance

233.6 miles 376 km · straight line
292 miles estimated 470 km · driving distance
5h 53min estimated drive time
$28 - $35 estimated fuel cost
~58min flight time
333° NNW bearing direction

How far is Knoxville from Seymour?

The distance from Knoxville to Seymour is 233.6 miles (376 km) as the crow flies. Seymour is located NNW of Knoxville. By car, the driving distance is approximately 292 miles, taking about 5h 53min. A direct flight would take roughly 58min. Both are located in United States — Knoxville in Tennessee and Seymour in Indiana.

For a drive of this length, it's recommended to plan at least one quick rest stop to stretch your legs and grab a coffee. Since you'll be heading mostly West, pack a good pair of sunglasses if you plan to drive during the late afternoon to avoid the harsh sun glare.

Coordinates come from public place data for Knoxville and Seymour. The driving distance is estimated from straight-line distance with a road-factor model, so confirm the route in your navigation app. Fuel, flight, bus, and train values are planning estimates and can change by date, provider, road closures, and border rules.

How to Get from Knoxville to Seymour

Method Time Est. Cost Best For
Drive 5h 53min $28 - $35 Flexible stops
Fly ~58min $80–200* Speed
Bus ~7h 4min $23–$44* Budget
Train ~5h 35min $35–$102* Comfort

Suggested Stops Between Knoxville & Seymour

Quick Facts

Knoxville
35.96°N, 83.92°W
America/New_York
276m elevation
Seymour
38.96°N, 85.89°W
America/Indiana/Indianapolis
184m elevation
Explore more routes from Seymour

Did You Know?

  • At walking speed (3 mph), it would take about 78 hours of non-stop walking
  • By bicycle at 12 mph, the journey would take roughly 19 hours
  • You could travel this distance about 106.6 times to circle the Earth's equator
Data Sources & Estimate Notes GeoNames · OpenStreetMap · Driving distance estimated using road factor coefficients