Johnson City to Seymour: Road Trip Guide & Distance

266.1 miles 428.3 km · straight line
332.7 miles estimated 535.4 km · driving distance
6h 42min estimated drive time
$32 - $39 estimated fuel cost
~1h 2min flight time
314° NW bearing direction

How far is Johnson City from Seymour?

The distance from Johnson City to Seymour is 266.1 miles (428.3 km) as the crow flies. Seymour is located NW of Johnson City. By car, the driving distance is approximately 332.7 miles, taking about 6h 42min. A direct flight would take roughly 1h 2min. Both are located in United States — Johnson City in Tennessee and Seymour in Indiana.

For a drive of this length, it's recommended to plan at least one quick rest stop to stretch your legs and grab a coffee. Since you'll be heading mostly West, pack a good pair of sunglasses if you plan to drive during the late afternoon to avoid the harsh sun glare.

Coordinates come from public place data for Johnson City and Seymour. The driving distance is estimated from straight-line distance with a road-factor model, so confirm the route in your navigation app. Fuel, flight, bus, and train values are planning estimates and can change by date, provider, road closures, and border rules.

How to Get from Johnson City to Seymour

Method Time Est. Cost Best For
Drive 6h 42min $32 - $39 Flexible stops
Fly ~1h 2min $80–200* Speed
Bus ~8h 2min $27–$50* Budget
Train ~6h 22min $40–$116* Comfort

Suggested Stops Between Johnson City & Seymour

Quick Facts

Johnson City
36.31°N, 82.35°W
America/New_York
498m elevation
Seymour
38.96°N, 85.89°W
America/Indiana/Indianapolis
184m elevation
Explore more routes from Seymour

Did You Know?

  • At walking speed (3 mph), it would take about 89 hours of non-stop walking
  • By bicycle at 12 mph, the journey would take roughly 22 hours
  • You could travel this distance about 93.6 times to circle the Earth's equator
Data Sources & Estimate Notes GeoNames · OpenStreetMap · Driving distance estimated using road factor coefficients