Jacksonville, Florida to Syracuse, New York: Road Trip Guide & Distance
How far is Jacksonville, Florida from Syracuse, New York?
The distance from Jacksonville, Florida to Syracuse, New York is 929.5 miles (1495.9 km) as the crow flies. Syracuse, New York is located NNE of Jacksonville, Florida. By car, the driving distance is approximately 1075.3 miles, taking about 20h 29min. A direct flight would take roughly 2h 22min. Both are located in United States — Jacksonville, Florida in Florida and Syracuse, New York in New York.
This is a serious multi-day road trip! We strongly recommend breaking this journey up with an overnight stay to ensure you arrive safely and refreshed. Heading East means you'll be driving into the sunrise if you start early. Keep your windshield clean for the best visibility. For a trip of this distance, flying is significantly faster. However, driving offers the flexibility to explore stops along the way.
Coordinates come from public place data for Jacksonville, Florida and Syracuse, New York. The driving distance uses an OSRM road-route result when route data is available. Fuel, flight, bus, and train values are planning estimates and can change by date, provider, road closures, and border rules.
How to Get from Jacksonville, Florida to Syracuse, New York
Suggested Stops Between Jacksonville, Florida & Syracuse, New York
- 1411 mi
- 2423 mi
- 3126 mi
- 4510 mi
- 5672 mi
Quick Facts
Did You Know?
- At walking speed (3 mph), it would take about 310 hours of non-stop walking
- By bicycle at 12 mph, the journey would take roughly 77 hours
- You could travel this distance about 26.8 times to circle the Earth's equator