Jacksonville, Florida to Sanibel Island: Road Trip Guide & Distance

How far is Jacksonville, Florida from Sanibel Island?

The distance from Jacksonville, Florida to Sanibel Island is 269.2 miles (433.3 km) as the crow flies. Sanibel Island is located S of Jacksonville, Florida. By car, the driving distance is approximately 336.5 miles, taking about 6h 46min. A direct flight would take roughly 1h 2min. Both are located in United States.

For a drive of this length, it's recommended to plan at least one quick rest stop to stretch your legs and grab a coffee.

Coordinates come from public place data for Jacksonville, Florida and Sanibel Island. The driving distance is estimated from straight-line distance with a road-factor model, so confirm the route in your navigation app. Fuel, flight, bus, and train values are planning estimates and can change by date, provider, road closures, and border rules.