Harrisonburg to Lake Placid: Road Trip Guide & Distance

475.7 miles 765.6 km · straight line
570.9 miles estimated 918.7 km · driving distance
11h 29min estimated drive time
$55 - $68 estimated fuel cost
~1h 27min flight time
31° NNE bearing direction

How far is Harrisonburg from Lake Placid?

The distance from Harrisonburg to Lake Placid is 475.7 miles (765.6 km) as the crow flies. Lake Placid is located NNE of Harrisonburg. By car, the driving distance is approximately 570.9 miles, taking about 11h 29min. A direct flight would take roughly 1h 27min. Both are located in United States — Harrisonburg in Virginia and Lake Placid in New York.

This is a solid day of driving. Be sure to take breaks every 2-3 hours to avoid driver fatigue, and plan your meals ahead of time. Heading East means you'll be driving into the sunrise if you start early. Keep your windshield clean for the best visibility.

Coordinates come from public place data for Harrisonburg and Lake Placid. The driving distance is estimated from straight-line distance with a road-factor model, so confirm the route in your navigation app. Fuel, flight, bus, and train values are planning estimates and can change by date, provider, road closures, and border rules.

How to Get from Harrisonburg to Lake Placid

Method Time Est. Cost Best For
Drive 11h 29min $55 - $68 Flexible stops
Fly ~1h 27min $80–200* Speed
Bus ~13h 47min $46–$86* Budget
Train ~10h 55min $69–$200* Comfort

Suggested Stops Between Harrisonburg & Lake Placid

Quick Facts

Harrisonburg
38.45°N, 78.87°W
America/New_York
404m elevation
Lake Placid
44.28°N, 73.98°W
America/New_York
570m elevation
Explore more routes from Lake Placid

Did You Know?

  • At walking speed (3 mph), it would take about 159 hours of non-stop walking
  • By bicycle at 12 mph, the journey would take roughly 40 hours
  • You could travel this distance about 52.3 times to circle the Earth's equator
Data Sources & Estimate Notes GeoNames · OpenStreetMap · Driving distance estimated using road factor coefficients