Christiansburg to Lexington, North Carolina: Road Trip Guide & Distance
How far is Christiansburg from Lexington, North Carolina?
The distance from Christiansburg to Lexington, North Carolina is 90.7 miles (145.9 km) as the crow flies. Lexington, North Carolina is located S of Christiansburg. By car, the driving distance is approximately 113.3 miles, taking about 2h 17min. A direct flight would take roughly 41min. Both are located in United States — Christiansburg in Virginia and Lexington, North Carolina in North Carolina.
This is a quick and easy drive, perfect for a day trip or weekend getaway. You can easily make the round trip in a single day. Given the short distance, driving or taking a train is often faster and more convenient than dealing with airport security and flight boarding times.
Coordinates come from public place data for Christiansburg and Lexington, North Carolina. The driving distance is estimated from straight-line distance with a road-factor model, so confirm the route in your navigation app. Fuel, flight, bus, and train values are planning estimates and can change by date, provider, road closures, and border rules.
How to Get from Christiansburg to Lexington, North Carolina
Suggested Stops Between Christiansburg & Lexington, North Carolina
- 181 mi
- 271 mi
- 327 mi
- 422 mi
- 523 mi
Quick Facts
Did You Know?
- At walking speed (3 mph), it would take about 30 hours of non-stop walking
- By bicycle at 12 mph, the journey would take roughly 8 hours
- You could travel this distance about 274.7 times to circle the Earth's equator