Charleston, West Virginia to Seymour: Road Trip Guide & Distance

How far is Charleston, West Virginia from Seymour?

The distance from Charleston, West Virginia to Seymour is 233.5 miles (375.8 km) as the crow flies. Seymour is located WNW of Charleston, West Virginia. By car, the driving distance is approximately 291.9 miles, taking about 5h 52min. A direct flight would take roughly 58min. Both are located in United States — Charleston, West Virginia in West Virginia and Seymour in Indiana.

For a drive of this length, it's recommended to plan at least one quick rest stop to stretch your legs and grab a coffee. Since you'll be heading mostly West, pack a good pair of sunglasses if you plan to drive during the late afternoon to avoid the harsh sun glare.

Coordinates come from public place data for Charleston, West Virginia and Seymour. The driving distance is estimated from straight-line distance with a road-factor model, so confirm the route in your navigation app. Fuel, flight, bus, and train values are planning estimates and can change by date, provider, road closures, and border rules.