Altus to San Angelo: Road Trip Guide & Distance
How far is Altus from San Angelo?
The distance from Altus to San Angelo is 228.4 miles (367.6 km) as the crow flies. San Angelo is located SSW of Altus. By car, the driving distance is approximately 285.5 miles, taking about 5h 45min. A direct flight would take roughly 58min. Both are located in United States — Altus in Oklahoma and San Angelo in Texas.
For a drive of this length, it's recommended to plan at least one quick rest stop to stretch your legs and grab a coffee. Since you'll be heading mostly West, pack a good pair of sunglasses if you plan to drive during the late afternoon to avoid the harsh sun glare.
Coordinates come from public place data for Altus and San Angelo. The driving distance is estimated from straight-line distance with a road-factor model, so confirm the route in your navigation app. Fuel, flight, bus, and train values are planning estimates and can change by date, provider, road closures, and border rules.
How to Get from Altus to San Angelo
Suggested Stops Between Altus & San Angelo
- 1153 mi
Quick Facts
Did You Know?
- At walking speed (3 mph), it would take about 76 hours of non-stop walking
- By bicycle at 12 mph, the journey would take roughly 19 hours
- You could travel this distance about 109 times to circle the Earth's equator