Alexandria to San Angelo: Road Trip Guide & Distance

471.4 miles 758.6 km · straight line
565.6 miles estimated 910.3 km · driving distance
11h 23min estimated drive time
$54 - $67 estimated fuel cost
~1h 27min flight time
273° W bearing direction

How far is Alexandria from San Angelo?

The distance from Alexandria to San Angelo is 471.4 miles (758.6 km) as the crow flies. San Angelo is located W of Alexandria. By car, the driving distance is approximately 565.6 miles, taking about 11h 23min. A direct flight would take roughly 1h 27min. Both are located in United States — Alexandria in Louisiana and San Angelo in Texas.

This is a solid day of driving. Be sure to take breaks every 2-3 hours to avoid driver fatigue, and plan your meals ahead of time. Since you'll be heading mostly West, pack a good pair of sunglasses if you plan to drive during the late afternoon to avoid the harsh sun glare.

Coordinates come from public place data for Alexandria and San Angelo. The driving distance is estimated from straight-line distance with a road-factor model, so confirm the route in your navigation app. Fuel, flight, bus, and train values are planning estimates and can change by date, provider, road closures, and border rules.

How to Get from Alexandria to San Angelo

Method Time Est. Cost Best For
Drive 11h 23min $54 - $67 Flexible stops
Fly ~1h 27min $80–200* Speed
Bus ~13h 40min $45–$85* Budget
Train ~10h 49min $68–$198* Comfort

Suggested Stops Between Alexandria & San Angelo

Quick Facts

Alexandria
31.31°N, 92.45°W
America/Chicago
23m elevation
San Angelo
31.46°N, 100.44°W
America/Chicago
562m elevation
Explore more routes from San Angelo

Did You Know?

  • At walking speed (3 mph), it would take about 157 hours of non-stop walking
  • By bicycle at 12 mph, the journey would take roughly 39 hours
  • You could travel this distance about 52.8 times to circle the Earth's equator
Data Sources & Estimate Notes GeoNames · OpenStreetMap · Driving distance estimated using road factor coefficients