Albany, New York to Jacksonville, Florida: Road Trip Guide & Distance

How far is Albany, New York from Jacksonville, Florida?

The distance from Albany, New York to Jacksonville, Florida is 956.6 miles (1539.5 km) as the crow flies. Jacksonville, Florida is located SSW of Albany, New York. By car, the driving distance is approximately 1072.7 miles, taking about 20h 27min. A direct flight would take roughly 2h 25min. Both are located in United States — Albany, New York in New York and Jacksonville, Florida in Florida.

This is a serious multi-day road trip! We strongly recommend breaking this journey up with an overnight stay to ensure you arrive safely and refreshed. Since you'll be heading mostly West, pack a good pair of sunglasses if you plan to drive during the late afternoon to avoid the harsh sun glare. For a trip of this distance, flying is significantly faster. However, driving offers the flexibility to explore stops along the way.

Coordinates come from public place data for Albany, New York and Jacksonville, Florida. The driving distance uses an OSRM road-route result when route data is available. Fuel, flight, bus, and train values are planning estimates and can change by date, provider, road closures, and border rules.